You can see that there are 4 rows where tiles are missing, and you can use the minimum and maximum size of the adjacent tiles in a row to assume how many can fit in each row, because the lines formed by edges WILL all line up. It’s all about deciding where the boundaries are.
As a Tetris player, it’s 2 T-pieces and a line-piece. Each Tetris piece is 4 squares (Tetris = tetra (meaning 4) + Tennis). 3 Tetris pieces times 4 squares each = 12 tiles
12, right?
Yes. That’s how many I counted.
How can you count something that isn’t there?
Behold! The invention of negative numbers.
You can see that there are 4 rows where tiles are missing, and you can use the minimum and maximum size of the adjacent tiles in a row to assume how many can fit in each row, because the lines formed by edges WILL all line up. It’s all about deciding where the boundaries are.
Assuming they are square tiles, yes. It’s also possible to tile the area with 6 2x1 tiles.
But all the tiles around the hole are squares
More like 4 2×1 tiles:![](https://lemmy.world/pictrs/image/2432bc45-8361-4906-a213-ca8cbcf9666c.jpeg)
Those are not 2x1 tiles.
For anyone having trouble visualizing it…
Ty; the weird angle was messing with my brain.
As a Tetris player, it’s 2 T-pieces and a line-piece. Each Tetris piece is 4 squares (Tetris = tetra (meaning 4) + Tennis). 3 Tetris pieces times 4 squares each = 12 tiles
Or 3 Z pieces…